Physics, asked by HONEY2027, 1 year ago

A balloon is at a height of 81 M and is ascending upwards with a velocity of 12m/s. A body of 2 kg weight is dropped from it. If g= 10m/s^2. The body will reach the surface of the earth in how much time?

Answers

Answered by Shaizakincsem
166
Since we're observing the vertical motion of the balloon that's ascending, for that we can use the equation as shown below. 

d = vt + 1/2 at²


where d is the height, v is the velocity, a is the acceleration, and t is the time.

Given that the balloon reached a height of 81 m at a velocity of 12 m/s².

Since a body is dropped and is going downwards, acceleration is equal to g = 10 m/s². So, plugging this into the equation, we have


81 = 12t + 1/2 (-10) t²
81 = 12t - 5t²

- 5t² + 12t - 81 = 0


Seeing that we have a quadratic equation, we can apply the quadratic formula to look for its positive root (we neglect the negative root since time cannot be negative). 


t = -(12)- √(12)³ - 4 (-5) (81)/ 2 (-5)

t = 5.4


This means that it will take 5.4 seconds for the body to reach the ground.

Answer: 5.4 seconds
Answered by Hello08
30

The correct answer is 5.4 seconds.

Thanks.

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