Question

a balloon is flowing up with a steady velocity of 12m/s^2 at a height of 32 m above the ground and an object is dropped from it .how long does it take for the object to reach the ground??

Answer 1

Given,

Take upward direction as -ve and downward direction as +ve.

u=−12m/s

h=65m

g=10m/s

2

v=0m/s

From 2nd equation of motion,

h=ut+

2

1

gt

2

65=−12t+

2

1

×10t

2

65=−12t+5t

2

5t

2

−12t−65=0

5t(t−5)+13(t−5)=0

t−5=0,5t+13=0

t=−

5

13

,5

Time taken to reach the ground is 5sec.

The correct option is A.