Question

A balloon is going upward with a velocity 20m/s. it releases a packet when it is at height 25m from the ground. How much time the packet will take to reach the ground in sec. (g=10m/s^2)

Answer 1

Answer:

Answer is 5

Explanation:

Given,

Take upward direction as -ve and downward direction as +ve.

u=−12m/s

h=65m

g=10m/s

2

v=0m/s

From 2nd equation of motion,

h=ut+

2

1

gt

2

65=−12t+

2

1

×10t

2

65=−12t+5t

2

5t

2

−12t−65=0

5t(t−5)+13(t−5)=0

t−5=0,5t+13=0

t=−

5

13

,5