A balloon is going upward with velocity 12m/s .it release a packet when it is at height of 65m from the ground .how much time the packet will take to reach the ground
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When the packet is released from the ballon , it moves up with the same speed as that of the ballon.
here,
h = - 65m ( -ive sign is b'coz the packet is moving downwards)
u = 12 m/s
a = g = --10 m/s ( taking the value of g as 10 m/s is convenient for this numerical)
Using, h = ut + 1/2 a t2
-65 = 12t - 1/2 *10t2
-65 = 12t - 5t2
5t2 - 12t - 65 = 0
5t2 - 25t + 13t - 65 = 0
5t ( t - 5 ) + 13( t - 5) = 0
( t - 5)(5t + 13) = 0
t =5 or t = -13/5
Since time can never be negative, the packet will take 5 sec. to reach the grond.
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here,
h = - 65m ( -ive sign is b'coz the packet is moving downwards)
u = 12 m/s
a = g = --10 m/s ( taking the value of g as 10 m/s is convenient for this numerical)
Using, h = ut + 1/2 a t2
-65 = 12t - 1/2 *10t2
-65 = 12t - 5t2
5t2 - 12t - 65 = 0
5t2 - 25t + 13t - 65 = 0
5t ( t - 5 ) + 13( t - 5) = 0
( t - 5)(5t + 13) = 0
t =5 or t = -13/5
Since time can never be negative, the packet will take 5 sec. to reach the grond.
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Dima:
There's only one problem though, the h cannot be in negative because the length can never be measured in negative. So it's 65 and not -65, maybe only g can be -ve when going up. But otherwise good answer though
yeah sorry
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