Question

a balloon is inflated with helium gas at room temperature of 25 degree Celsius at 1 bar pressure when its initial volume was 2.27 and was allowed to rise in the air as it rises in the air external pressure decreases and the volume of the gas increases feel finally it's burst when the external pressure is 0.3 what is the limit to which volume of the balloon can be inflated​

Answer 1

Hey Dear,

◆ Answer -

Max volume = 7.567 L

◆ Explaination -

# Given -

T = 25 ℃ = 298 K

P1 = 1 bar

V1 = 2.27 L

P2 = 0.3 bar

# Solution -

Applying Boyle's law to rising balloon,

P1.V1 = P2.V2

V2 = P1.V1 / P2

V2 = 1 × 2.27 / 0.3

V2 = 7.567 L

Therefore, maximum limit to which the balloon can be inflated is 7.567 L.

Hope this helps you...

Answer 2

Answer:

hope it will help you.

Explanation:

given by using wireless law fee is equal to 25 degree Celsius which is equal to 25 + 273 kelvin is equal to 298 K value then 1 is equal to 1 back and we 1 is equal to 2.27 later and P2 is equal to 0.3 back by using while or flop even into V1 is equal to 2 into 2 therefore Bitu is equal to p 1 INR to be one upon P2 therefore we 2 is equal to 1 INR to 2.2 7.0.3 therefore maximum value of volume is 7.567 litres