Physics, asked by ShivamKashyap08, 18 days ago

A Balloon is moving upwards with a speed of 20m/s. When it is at a height of 14m from ground in front of a plane mirror in situation as shown in figure, a boy drops himself from the balloon. Find the time duration for which he will see the image of sources S placed symmetrically before plane mirror during free fall.

Chapter:- Ray optics and optical instruments.
Class:- 12

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Answered by ItzSameeksha01
92

\longrightarrow\large\bold{\underline{\underline{\sf{\red{Question :-}}}}}

A Balloon is moving upwards with a speed of 20m/s. When it is at a height of 14m from ground in front of a plane mirror in situation as shown in figure, a boy drops himself from the balloon. Find the time duration for which he will see the image of sources S placed symmetrically before plane mirror during free fall.

\longrightarrow\large\bold{\underline{\underline{\sf{\green{Answer :-}}}}}

\large\underline{\underline{\bigstar{\textbf{\textsf{\: Diagram \: is \: in \: attachment\::-}}}}}

 \frac{FQ}{BF}  =  \frac{IH}{BH}  =  \frac{HS}{BH}  \\  \\

\therefore

FQ = (BF)( \frac{HS}{BH} ) \\  \\

(5)( \frac{1.0}{0.5} ) \\  \\

10 m

\dashrightarrowFC = 2 + 10 = 12 m

v = 20 m/s

Distance (s) = -12

Initial velocity (u) = 20

Time (t) = ?

❒ Second Equation Of Motion Formula :

\begin{gathered}\begin{gathered}\mapsto \sf\boxed{\bold{\pink{s =\: ut + \dfrac{1}{2} at^2}}}\\\end{gathered}\end{gathered}

Put values in given equation -

We will get -

➻ t1 = 4.535 sec

v = √(20)² - 2 × 10 × 10

\large\underline{\blue{\underline{\frak{\pmb{ 14.14 \: m/s }}}}}

\begin{gathered}\begin{gathered}\mapsto \sf\boxed{\bold{\gray{v² - u² = 2gh}}}\\\end{gathered}\end{gathered}

➻ t2 = 2v/g

\large\underline{\orange{\underline{\frak{\pmb{ 2.83\: s }}}}}

\thereforeTime required = t1 - t2

\qquad\qquad{\underline{\pmb{\purple{\mathcal{1.7 s}}}}}

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