Question

A balloon is raising vertically up with a velocity of 10m/s. When it is at height of 45m a stone is released from it. When will the stone reach the ground?
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Answer 1

Answer:

2.16 seconds

Explanation:

Given :

• Initial velocity = u = 10 m/s

• Height from which the stone is dropped = s = 45 metres

• Acceleration due to gravity = a = 10 m/s²

To find:

• Time taken by the stone to fall down

Using the second equation of motion :

S=u×t+½×at²

45=10×t+½×10×t²

45=10t+5t²

5t²+10t-45=0

By solving the above quadratic equation, t = 2.16 seconds

The time taken by the stone to fall down is equal to 2.16 seconds

Answer 2

Answer:

Given:

• A balloon is raising vertically up with a velocity of 10m/s. When it is at height of 45m a stone is released from it.

Find:

• When will the stone reach the ground?

Using formula:

★ ${\sf{\underline{\boxed{\orange{\sf{H = u \times t+ 1/2 \times at^{2}}}}}}}$

Know terms:

1. Height = (H)
2. Initial velocity = (u)
3. Acceleration = (a)
4. Time = (t)

Calculations:

⇒ $\bold{45=10 \times t+ 1/2 \times 10 \times t^{2}}$

⇒ $\bold{45=10t+5t^{2}}$

⇒ $\bold{5t^{2} +10t-45 = 0}$

⇒ ${\sf{\underline{\boxed{\red{\sf{t = 2.16 \: sec}}}}}}$