A balloon is rising at 29.4 m/s. A stone fall from the balloon and reaches the ground in 20.0 s. How high is the balloon in meters when the stone is dropped?
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Answer:
The height is 2588 m
Explanation:
initial velocity of
the balloon, u= 29.4 m/s
time, t = 20s
Using 2nd eqn of motion,
h= ut + gt²/2 (let g= 10m/s²)
h= 29.4 × 20 + 10×(20)²/2
h= 588 + 4000/2
h= 1176 + 4000/2
h= 5176/2
h= 2588 m
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