Question

A balloon is rising vertically upwards at a velocity of 10 m/s. When it is at a height of 45 m from
the ground, a parachutist bails out from it. After 3 seconds he opens his parachute and decelerates
at a constant rate of 5 m/s. What was the height of the panichutist above the ground when he opened
his parachute ? (Take g = 10 m/s^2)
(1 ) 15 m
(2) 3 m
(3) 45 m
(4) 60 m​

Answer 1

Answer:

45 m is the answer of the question

Answer 2

Answer:

Given,

u=10m/s in upward direction.

g=−10m/s

2

in downward direction

t=3sec

H=45m

So by second equation of motion:

s=ut+

2

1

at

2

=10×3+

2

1

(−10)×3×3

=30−45

=−15m

Here negative sign indicates that it is directed downwards.

So height from the ground when he opened parachute is =45−15=30m