A balloon is rising vertically upwards at a velocity of 10m/s. When it is at height of 45m from the ground, a parachutist bails out from it. After 3 seconds he opens his parachute and decelerates at a constant rate of 5m/s^2. what was the height of parachutist above ground when he opened his parachute?(g=10m/s^2)
Answers
When a balloon rising vertically upwards at a velocity of 10m/s at a height of 45 m from the ground parachutist bails out from the balloon . After 3s. He opens the parachute and decelerates at a constant rate of 5m/s^-2. (a)what is the height of the parachute above the ground when he opens the parachute (b). How far is he from the balloon at this instant (c) With what velocity does he strike the ground (d) what time does he take in striking the ground after his exit from the balloon (g=10m/s^-2)
These images can speak for themself, but the key points to remember is
#inertia
#max height achieved
#total time taken in upward and then in downward motion.
If you get these , you could solve the sum , but here is what i got anyways.
Hope it would help!!
Cheeers!!
