Question

A balloon is rising vertically upwards with a velocity of 10m/s. When it is at a height of 45m from the ground, a stone is released from it. When will the stone reach the ground?

Answer 1

Answer:

hlo dear ❤

Step-by-step explanation:

When the parachutists bails out, he has same velocity of the balloon.

u=10m/s in upward direction.

g=-10ms2 in downward direction

t=3sec

so by second equation of motion:

s=ut+1/at²

=10x3+1/2(-10)x 3x3

=30-45s

=-15m

Here negative sign indicates that it is directed downwards.

So height from the ground when he opened parachute is =45-15=30m

b) time=3sec

balloon rises through 30m

Balloon velocity=10m/s

Hence parachute is 30+15=45m away from balloon.

c) The velocity of parahute=?

 time=3sec

V=u+gt

=10-10x3

=-20m/s directed downwards.

at time t=3sec

u=-20m/s

displacemnt s=-30m

a=+5m/s2 upwards

time taken=t=?

s=ut+1/at²

-30=-20t+5/2 t²

t²-8t+12=0

t²-6t-2t+12=0

t(t-6)-2(t-6)=0

t=6 or 2 sec

if t=6 sec then velocity with which he hits the ground will be V=u+at

V=-20+5x6 =10m/s

which is in upward direction not possible.

Hence t=2sec

V=-20+5x2=-10m/sWhich will be in downward direction.

d)  The total time parachutist takes to hit ground=3s+2s=5sec..