a balloon is rising with a velocity 29 m/s .a stone dropped from balloon reaches the ground in 10 second.calculate the height from which stone is dropped?
Answers
Explanation:
u=29m/s
t=10s
a=?
s=?
v=0m/s
Now we have to find Acceleration.
a=v - u/ t
a=0 - 29 / 10
a=2.9m/s²
Now we can find distance or height.
s=ut + 1/2 at²
s=29×10+1/2×2.9×10×10
s=290+1/2×290
s=145+290
s=435m
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Answer:
The height from which stone is dropped is 200 m.
Explanation:
The balloon is rising upwards. The stone is dropped down from it. So the initial velocity of the stone will have a negative sign.
The initial velocity of the stone, u = -29 m/s
The time taken by the stone to reach the ground, t = 10 s
The value of acceleration due to gravity, g = 9.8 m/s²
The distance traveled by the stone will be equal to the height from which it is dropped. This distance can be found using the 2nd equation of motion.
S = ut + (at²/2)
S = -29 × 10 + ((9.8 × 10²)/2)
S = -290 + 490
S = 200 m