Question

. A balloon moving in a straight line, passes above two points A and B on the ground. When it is vertically above point A, its angle of elevation at point B is found to be 60°. When it is vertically above point B, its angle of elevation as observed from A is found to be 45°. Points A and B are 1000m apart. Find the distance of the point from A, where it touches the round.

Answer 1

Answer:

2366.12m

Step-by-step explanation:

From the attached image:

h1 = 1000Tan60 = 1732m

h2 = 1000Tan45 = 1000m

Triangle ADC is similar to triangle BEC

So,

1732/1000 = (1000+x)/x

1732x = 1000000 + 1000x

732x = 1000000

x = 1366.12m

Distance AC = 1000 + 1366.12

Distance AC = 2366.12m