A balloon of mass m descending with an acceleration
a.what mass be dropped from the balloon so that it may go up with the same acceleration a?
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Take upward direction to be the positive y-direction. If m is the mass thrown out, then the equation of motion for before and after the mass m is thrown out are
Ma = F – Mg
(M–m)a = F – (M–m)g
Solving the two equations m =2ma/(a+g)
Consider the balloon to move along y axis. The balloon`s mass is mThen, when it is descending,ma=F-mgAfter removing mass m`, the balloon ascends, then(m-m`)a=F-mgSolve the equations, then m`=2ma/a+g
Consider the balloon to move along y axis. The balloon`s mass is mThen, when it is descending,. ma=mg-F. After removing mass m`, the balloon ascends, then. (m-m`)a=F-(m-m`)g. Solve the equations, then m`=2ma/a+g
Ma = F – Mg
(M–m)a = F – (M–m)g
Solving the two equations m =2ma/(a+g)
Consider the balloon to move along y axis. The balloon`s mass is mThen, when it is descending,ma=F-mgAfter removing mass m`, the balloon ascends, then(m-m`)a=F-mgSolve the equations, then m`=2ma/a+g
Consider the balloon to move along y axis. The balloon`s mass is mThen, when it is descending,. ma=mg-F. After removing mass m`, the balloon ascends, then. (m-m`)a=F-(m-m`)g. Solve the equations, then m`=2ma/a+g
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