A balloon of volume V contains a gas of mass m at a pressure P and temperature 15°C. Gas is pumped into the balloon so that its volume is doubled and the pressure is trebled. If the temperature increases 6°C in the process, find the ratio of the increase in mass to the original mass.
A) 34 : 5
B)239: 49
C) 199 : 21
D) 3:4
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Answer:
B) 239:49
Step-by-step explanation:
V2 = 2 x V1
P2 = 3 x P1
T1 = 288K T2 = 294K
By Ideal Gas Equation (P1 x V1 x T2) / (P2 x V2 x T1) = m1 / m2
Substitute the above values we get;
m1 / m2 = 49/288
Increase In mass = m2 - m1 = 288 - 49 = 239
Increase in mass : m1 = 239 : 49
Hope It helps You!!!!
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