A balloon prices with constant acceleration 1.25 metre per second square from ground after 8 second a stone is dropped from the bedroom then find out displacement of the squares till it reaches on the ground
Answers
Answer:
Solution is in the attachment
Answer:
4SECONDS
Explanation:
Steps:
1) Initially,
Initial velocity, u = 0m/s
acceleration, a =1.25 m/s^2
Velocity of balloon after 8 s, v = u +at
=> v = 0 + 1.25 * 8 = 10m/s
2) Displacement of balloon in 8 s,
S=ut+1/2at^2
=>0+1/2x1. 25x8^2=>40m
3) After t = 8s, a stone is dropped.
Initial velocity of stone at time of fall is same as that of balloon at that time :
That is velocity of stone,when it is dropped is 10m/s upward.
Initial velocity, u = 10m/s
Displacement, s = -40m ( - means downward)
Balloon is left.
Acceleration, a = -10 m/s^2
So, time taken by stone to reach the
S=ut+1/2at^2
-40=10t+1/2x(-10)xt^2
=>t^2-2t-8=0
=>(t+2)(t-4)=0
=>t=-2 (or) t=4
t = 4 s, t = -2 (rejected)
Therefore, Stone will take 4 seconds to reach the ground after being dropped from balloon at height h =40m from ground.