a balloon rises from rest with a constant acceleration g/8
. a stone is released from it when it has risen to height h . find the time taken by the stone to reach the ground
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Velocity after rising height h
v = sqrt(2aS) ………[∵ initial velocity of balloon is zero]
v = sqrt(2 × g/8 × h)
v = sqrt(gh/4)
This is the initial velocity of stone.
Time taken by stone rise extra height and come to it’s point of projection is
t1 = 2u / g
= 2 × sqrt(gh/4) / g
= sqrt(h / g)
Final velocity of stone when it touches the ground
v’ = sqrt(u^2 + 2aS)
= sqrt[(gh/4) + 2gh]
= sqrt[2.25 gh]
= 1.5 × sqrt(gh)
Time taken by stone to fall down from point of projection
t2 = (v’ - u) / a
= [(1.5 × sqrt(gh)) - sqrt(gh/4)] / g
= sqrt(gh) [1.5 - 0.5] / g
= sqrt(h / g)
Total time taken for stone to reach the ground
T = t1 + t2
= 2 sqrt(h / g)
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