Question

A balloon rising up with constant velocity of 10m\s at height 15m from ground at that instant a stone of mass 1kg dropped from it find kinetic energy of sto e just before reaching at ground

Answer 1

Answer:

200J

Explanation:

Refer to the material.

Answer 2

The kinetic energy of stone  just before reaching at ground is 200 J.

Explanation:

Given the height h = 15 m.

The mass of the stone, m = 1 kg.

The velocity of the stone is v = 10 m/s because balloon rising with constant velocity.

The potential energy at height

U = mgh = 1 kg x 10 m/s^2 x 15 = 150 J.

The initial kinetic energy,

$K=\frac{1}{2}mv^2$

$K=\frac{1}{2}1kg\times(10m/s)^2$

K =50 J.

The final potential energy at ground is u = zero (because height is zero).

Let the final kinetic energy is k.

Therefore, from conservation of energy,

initial potential energy (U) + initial kinetic energy (K) = final potential energy (u) + final kinetic energy (k).

substitute the values, we get

150 J+ 50 J = 0 + k

k = 200 J.

Thus, the kinetic energy of stone  just before reaching at ground is 200 J.

#Learn More: conservation of energy.

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