Question

A balloon rising vertically up witha velocity of 5m/s drops a body from a height of 20m, above the ground the velocity of the body at 1s. After the release is

Answer 1

Heya!!

Let's Discuss some basic concepts before solving this problem.

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£ When a body drops from balloon it will attain the velocity of balloon. The initial velocity of body will be 5m/s vertically upward ( y? ) and the acceleration is equal to g in vertically downwards. The body continuously to move upward for some time ( till it's speed becomes zero ) and then it falls vertically downwards and hit the ground.

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Exp:-

V² - u² = - 2gh

v = 0 ( At the top ) , u = 5m/s

h = 25/20

h = 1.25m

Time taken to reach the height 1.25m is

given by

v = u -gt

v = 0 ( At the top )

u = gt

t = 5/10

t = 0.5s

At t = 1s h = 2.5m

Velocity at t = 1s is given by

-v² - u² = - 2gh

v = ? , u = 5m/s ,g = 10m/s² and h =2.5m

-v² = -50 + 25

-v² = -25

v = 5m/s

Answer 2

Explanation:

v=4.8m/s by solving using equations of motion