A balloon’s internal pressure is 1.25 atm, and its volume is 2.50 L. If the balloon is taken to the bottom of the ocean (pressure = 95.0 atm), what would be its new volume? Assume that the temperature does not change. (Round to the nearest hundredth place)
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if temperature constant then according Boyle's law p is inversely promotional to v mean pv= constant using p1v1= p2v2 here 1.25×2.5= 95×v2 after solving v2= 0 .032 l
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