Question

A balloon starting from rest ascends
vertically with uniform acceleration to a
height of 100 m in 10 s. The force on
the bottom of the balloon by a mass of
50 kg is
(g = 10 ms?)
(a) 100 N
(b) 300N
(c) 600N
(d) 400 N
[EAMCET 2013]​

Answer 1

Answer :-

F = 100 N

Option → A

Given :-

$h = 100 m \\ u = 0 m/s \\t = 10 s \\ m = 50 kg$

To find :-

The force exerted on the bottom of the balloon by a mass of 50 Kg.

Solution:-

First, we have to find the acceleration produced in the balloon.

• Using equation of motion.

$h = ut + \dfrac{1}{2} at^2$

• Put the given values,

→$100= 0 \times 10 + \dfrac{1}{2}\times a \times (10)^2$

→$100= \dfrac{1}{2}\times a \times 100$

→$100 = 50a$

→$a = \dfrac{100}{50}$

→$a = 2 m/s^2$

Force exerted by mass of 50 kg on balloon :-

• Using Newton 2nd law of motion.

→$F = ma$

→$F = 50 \times2$

→$F = 100 N$

hence,

Force exerted by mass on balloon is 100N.