A balloon starts from the ground and moves vertically upwards with an acceleration of 2 ms² . After 5s a stone is released from the balloon. Find the time taken by the stone to reach the ground.
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Here upward acceleration of balloon is 2 m/s² .
U=0
{V=U+AT}
so, velocity gained by the stone after 5 sec. =2×5=10m/s
v = 10m/s
s=ut+½at²
Height reached by stone upto the time at which it is released is ½×2×5×5 = 25m.
s=ut+½at²
initial velocity (u) = 0
v=u (initial velocity of stone when dropped )
S=ut+ ½gt²
25=10×t+½×10×t²
taking g =10m/s ²
and initial velocity is upward while net displacement is down so again negative.
5t² -10 t -25 =0
t²-2t-5=0
solving , we get t = 3.45sec.and t =1.45sec.
Time required to reach ground= 3.45 sec.
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