Question

a balloon starts rising from the ground vertically upwards uniformly at the rate of 1m sat the end of 4 second a body was released from the balloon calculate the time taken by the released body to reach the ground ​

Answer 1

Explanation:

speed= 1m/s

time = 4s

distance travelled by the balloon in these 4s =

$distance = \: speed \: \times time$

distance= 1×4

distance= 4 m

$tim e \: taken \: = \frac{distance}{speed}$

time = 4/1

time = 4 s

Answer 2

Answer:

Explanation:

Since it travels 1m in 1 second it will travel 4 m in 4 seconds.

h= ut + 1/2 gt^2

h=4 m

u=1 ms

g=10 ms^2

4= 1t + 1/2 x 10 x t^2

4= t + 5t^2

0= 5t^2 + t -4

Factorizing the above equation

0 = (5t+4)(t+1)

t=-1

But it is a scalar quantity and time cannot be negative so t = 1