Question

A balloon starts rising from the ground with an acceleration of 2m/s^2

Answer 1

Answer:

and the ballon reaches the sky

Answer 2

The balloon starts to rise vertically upward with an acceleration of 2m/s^{2}2m/s2 

After one second (First Case)

Therefore in this case; u = 0 ; t =1; a=2u=0;t=1;a=2 

The distance traveled in this case by the formula s=ut+ \frac{1}{2}at^{2}s=ut+21at2 

∴ s = 1m

Case Two:-

From there a stone was dropped...

Therefore the stone was falling under the effect of gravity

Therefore in this case; u=0;s=1;a=9.8u=0;s=1;a=9.8 

The time can be calculated in this case by the formula s=ut+ \frac{1}{2}at^{2}s=ut+21at2 

∴ t ≈ 0.45s

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