A balloon takes up 625L at 0°C. If it is heated to 80°C, what will its new volume be?
Answers
Answer:
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Pressure is constant.
Initial volume(v1) = 625 L.
Initial temperature(T1) = 0° C.
Final temperature(T2) = 80° C.
To find:
The final volume(v2)
Solution:
Initial volume(v1) = 625 L.
Initial temperature(T1) = 0° C.
= (0 + 273.15)
= 273.15 K.
Final temperature(T2) = 80° C.
= (80 + 273.15)
= 353.15 K
Pressure is constant.
Final volume(v2) = ?
From the formula we get,
(\dfrac{v1}{T1}) =( \dfrac{v2}{T2} )(
T1
v1
)=(
T2
v2
)
or, (\dfrac{625}{273.15} )=( \dfrac{v2}{353.15} )or,(
273.15
625
)=(
353.15
v2
)
or, (\dfrac{v2}{353.15}) = (\dfrac{625}{273.15} )or,(
353.15
v2
)=(
273.15
625
)
or, v2 = (625×353.15)/273.15
or, v2 = 853.81 L.
∴ The volume of