Math, asked by mahajandhanashri, 11 months ago

a balloon vendor has 2 red ,3 blue and 4 green balloons. he wants to choose one of them at random to give it to pranli what is the probabilty of the event that pranali gets
1 a red balloon
2 a blue balloon

Answers

Answered by Anonymous
7

Question:

A balloon vendor has 2 red ,3 blue and 4 green balloons. He wants to choose 1 of them at random to give it to pranli. What is the probabilty of the event that pranali gets _

1) a red balloon .

2) a blue balloon.

Answer:

1) The probability of getting a red baloon is \dfrac{2}{9}.

2) The probability of getting a blue balloon is \dfrac{1}{3}.

Given:

A balloon vendor has 2 red ,3 blue and 4 green balloons.

He wants to choose 1 of them at random to give it to pranli.

To find:

What is the probabilty of the event that pranali gets _

1) a red balloon .

2) a blue balloon.

Explanation:

The balloon vendor has 2 red, 3 blue and 4 green balloons.

So, total nuber of ballons_

(2+3+4)

= 9 balloons.

∴ In each case,

Total number of outcome = 9.

We know that,

Probability = (Number of favorable outcome/Total number of outcome)

1)

Number of red balloons = 2.

So, number of favorable outcome = 2.

∴ P.E.(getting a red balloon is) = \frac{2}{9}

∴ The probability of getting a red baloon is \dfrac{2}{9}.

2)

Number of blue balloon = 3

So, number of favourable outcome = 3.

∴ P.E. (getting a blue balloon) = \frac{3}{9}

                                               = \frac{1}{3} [∵ Dividing 3 and 9 by 3.]

∴ The probability of getting a blue balloon is \dfrac{1}{3}.

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