Question

A balloon with a charge of 4.0 µC is held a distance of 0.70 m from a

second balloon having the same charge. Calculate the magnitude of

the repulsive force.​

Answer 1

Answer: The magnitude of the repulsive force is 0.2938N.

Explanation:

The repulsive force is given as,

$F=\frac{kQ_1Q_2}{r^2}$      (1)

Where,

F=repulsive force present between the charges

k=Coulomb's constant=9×10⁹m²/C²

Q₁, Q₂=respective charges

r=distance between the charges

From the question we have,

Q₁=4μC=Q₂

Distance between the charges=0.70m

By substituting the required values in equation (1) we get;

$F=\frac{9\times 10^9\times 4 \times 10^-^6\times 4 \times 10^-^6}{(0.7)^2}$

$F=\frac{9\times 16\times 10^-^3}{0.49}$

$F=293.8\times 10^-^3$

$F=0.2938N$

Hence, the magnitude of the repulsive force is 0.2938N.

Answer 2

Answer:

0.2938

Explanation:

0.2938N is the answer of this question