A balloon with its contents weighing 160 N is moving down with an acceleration g/2m/s^2. The mss to be removed from it so that the balloon moves up with an acceleration of g/3m/s^2 is
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Answer:
F = Upward Force due to balloon
Before removing mass
Mg - F = Ma
160 - F = Mg/2
160 - F = 160/2
F = 80 N
After removal of mass (m)
F - (M - m)g = (M - m)a
F - (M - m)g = (M - m)g/3
F - Mg + mg = Mg/3 - mg/3
4mg/3 = 4Mg/3 - F
m = 3/(4g) × [4Mg/3 - F]
m = 3/(4 × 10) × [(4 × 160 / 3) - 80]
m = 10 kg
Mass to be removed is 10 kg
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