A baloon is accending at a rate of 40m/s. at a height of 98m/s from above ground when a packet is dropped from it. after how much time and with what velocity does it reaches the ground.
dityashahni:
ok
Idhar g kya h?
10 या 9.8?
9.8
is v = 59.66
or 60 m/s approx
answer nhi pata
Aapka kya aaya?
same
ha.. तब right h
Answers
Answered by
0
♥️Hope u like my process❤️
==========================
Diagram same as in image (1)
Sorry if handwriting is bad
_____________________________
♥️Hope this is ur required answer❤️
♥️Proud to help you ❤️
==========================
Diagram same as in image (1)
Sorry if handwriting is bad
_____________________________
♥️Hope this is ur required answer❤️
♥️Proud to help you ❤️
Attachments:
but i am chasmis..
I know...
ur previous pic.. has specs..
How??
u had remembered!!
yeah.. I told. u i never forgot the ones.. who are very trustful.. and talking to u.. also makes my mind refresh..
thanks for great appreciation..
thanks to u..!! ❤️♥️
to have a talk with me..
hmmm
Answered by
0
Initial velocity = 14 m/s upwards (therefore +ve) .
Using kinematic equations:
S=ut +12at212at2
-98 = 14t -1212 9.8 t2t2
From here, solving the quadratic eqn, we get t=57.857.8 secs (approx)
Now, velocity can be calculated by using conservation of energy :
12mv2=mgh12mv2=mgh
1212 v2=ghv2=gh
1212 v2=9.8×98v2=9.8×98
From here, v =98√598√5=43.8 m/s (approximately)
Similar questions