Question

A baloon is ascending at a height of 100 m above the ground when a packet is dropped from the ballon. After how much time does it reach the ground? (g=10m/s^2)

(please dont copy answer and answer is 5 second please tell me the explination)​

Answer 1

Explanation:

For the balloon,

Initial velocity, u = 14 m/s (upward)

Acceleration, a = -9.8 m/s2 (downward)

Displacement, h = -98 m (downward)

Using,

h = ut + ½ at2

=> -98 = 14t - 0.5 × 9.8 × t2

=> t = 6 s

Thus, the packet reaches the ground in 6 s.

Now, using,

v = u + at

=> v = 14 – 9.8 × 6 = -44.8 m/s (downward)

This is the velocity with which the packet reaches the ground.

Answer 2

Explanation:

This is Your Ans Mate!!

I hopes it will helps you♥️♥️