Question

A baloon rising vertically......................................ball hit the ground​

Answer 1

Answer :

Time = 6.2 s

Height = 193 m

Explanation :

Q) A balloon rising vertically up with unitrom velcity releases a ball at a deight of . Calculate the time taken by the ball to hit the ground and total height of balloon when ball hits the ground. Take g=10 m s^2

Ans ) Time = 6.2 s

Height = 193 m.

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Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{t = \frac{3 + \sqrt{89} }{2} \: sec}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\bold{\underline{Given :}}}$

$\tt: \implies Upward \: velocity(u) = {15 \: m/s}$

$\tt: \implies height(s ) = 100 \: m$

$\tt: \implies Acceleration \: due \: to \: gravity(g) = 10 \: {m/s}^{2}$

$\red{\bold{\underline{To \: Find:}}}$

$\tt: \implies Time \: taken(t) = ?$

• According to given question :

$\tt \circ \:Initial \: velocity = - 15 { \: m/s}$

$\bold{As \: we \: know \: that}$

$\tt: \implies s = ut + \frac{1}{2} a {t}^{2}$

$\tt: \implies 100 = - 15 \times t + \frac{1}{2} \times {10 \times t}^{2}$

$\tt: \implies 100 = - 15t + 5 {t}^{2}$

$\tt: \implies 5 {t}^{2} - 15t - 100 = 0$

$\tt: \implies {t}^{2} - 3t - 20 = 0$

$\tt: \implies t = \frac{ - ( - 3) \pm \sqrt{ { (- 3)}^{2} - 4 \times 1 \times - 20} }{2 \times 1}$

$\tt: \implies t = \frac{3 \pm \sqrt{89} }{2}$

$\green{\tt: \implies t = \frac{3 + \sqrt{89} }{2} \: sec}$