A,band c can do a piece of work in 36,54 and 72 days respectively.they started the work but a left 8 days before the completion of the work while b left 12 days before the completion.the number of days for which c worked is?
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so c works for 24 days
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C works for 24 days
Number of days in which A can do work = 36 (Given)
Number of days in which B can do work = 54 (Given)
Number of days in which C can do work = 72 (Given)
Let the work be completed in = x days.
Let C work for = x days
Then A will work for = (x - 8) days and B will works for = (x - 12) days.
Thus, according to the question,
[ (x−8)/36 (x−12)/ 54+x/72] = 1
[(6x−48+4x−48+3x)/216] =1
13x−96
=216
13x =216+96
13x = 312
x = 312/13
x = 24
Therefore, the number of days for which C worked was 24.
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