A,Band C can do a piece of work in 6 days,12 days and 24 days respectively.In what time will they altogether do it?
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Answered by
2
Answer:
A can do a piece of work in = 1/6 days
B can do a piece of work in = 1/12 days
C can do a piece of work in = 1/24 days
Total work they can do = 1/6+1/12+1/24= Lcm of 12,6,24=24
Total work = 7/24 days please mark as brainilest I want brainilest
Answered by
20
Solution :-
A can do a piece of a work is 6 days
B can do a piece of a work in 12 days
C can do a piece of a work in 24 days
Now,
The work done by A in 1 day = 1/6
The work done by B in 1 day = 1/12
The work done by C in one day = 1/24
Therefore,
The work done by ( A + B + C) together
= 1/6 + 1/12 + 1/24
= 4 + 2 + 1 / 24
= 7/24
A, B and C can do the work together
= 24/7 days = 3.3/7 days
[ Reciprocal of 7/24 = 24/7 ]
Hence, The work done by A, B and C together in 3.3/7 days 
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