A bank lent rs.4000 to person a at a certain rate of s.i and rs.5000 to b at 1/2 % more than that of
a. after 2 years the bank received rs.860 as interest from both a and
b.find the rate of interest p.a at which the amount was lent to b?
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Hey....... Bank loan amount for A=4000
Bank loan amount for B=5000
Interest method used by the bank is simple interest
also given that the amount is lent to B at a rate 1/2% higher than that of A
so if money is lent to A at x%
then for B it will be x + 1/2%
we know that
Simple Interest
= (Principal amount*Time*Rate)/100
a)amount recieved after 2years is 860 from both A and B
so we will subsitute the values in the formula
SI={4000*2*x/100} + {5000*2*(x+1/2%)}/100 =860
=(80*x) + (100*(x+ 0.5))=860
=80x + 100x + 100(0.5) = 860
= 180x + 50= 860
= x = 810/180 =4.5%
therefore percentage at which amount is lent to A is 4.5%
percentage at which amount is lent to B is 1/2times higher than B...So 1/2 =0.5
4.5+0.5=5%
therefore percentage at which amount is lent to B is 5%
Bank loan amount for B=5000
Interest method used by the bank is simple interest
also given that the amount is lent to B at a rate 1/2% higher than that of A
so if money is lent to A at x%
then for B it will be x + 1/2%
we know that
Simple Interest
= (Principal amount*Time*Rate)/100
a)amount recieved after 2years is 860 from both A and B
so we will subsitute the values in the formula
SI={4000*2*x/100} + {5000*2*(x+1/2%)}/100 =860
=(80*x) + (100*(x+ 0.5))=860
=80x + 100x + 100(0.5) = 860
= 180x + 50= 860
= x = 810/180 =4.5%
therefore percentage at which amount is lent to A is 4.5%
percentage at which amount is lent to B is 1/2times higher than B...So 1/2 =0.5
4.5+0.5=5%
therefore percentage at which amount is lent to B is 5%
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