A bank lets its constomers choose ,
personalidentification numbey (PIN)comprising of 2 character that can beAlpha numeric
What is the probability of someone correctlly guessing a bank Customer's PN in the first
attempt if no repeats are allowed
Answers
Step-by-step explanation:
(there are 10 numbers and 26 Alphabets=36 total)
therefore,we have to choose one num or alpha from 36 elements and next num or alpha from remaining 35 elements (since repetition is not allowed)
probability of formation of the number is,
= 36C1 * 35C1
=1260
and probability of correct guessing of PIN from 1260 elements is,
=1/1260
Given: A bank lets its costumers choose , personal identification number (PIN) comprising of 2 character that can be Alpha numeric
To Find : the probability of someone correctly guessing a bank Customer's PN in the first attempt if no repeats are allowed
Solution:
There are 26 letters (A to Z)
There are 10 digits ( 0 to 9)
Hence total available to select = 36
PIN can be alphanumeric means its not necessary to be alpha numeric but it can be only numeric or of alphabets.
Hence 2 out of 36 can be selected in
³⁶C₂ ways as repetition not allowed and 2 can be arranged in 2! ways
³⁶C₂ = 36 * 35/2
2! = 2
so total ways = 36 * 35 = 1260
Probability of someone correctly guessing a bank Customer's PN in the first attempt = 1/1260
Additional Info:
if Question was PIN must be alpha numeric
Then
there were ways to select ²⁶C₁*¹⁰C₁ *2!
= 26 * 10 * 2 = 520
Probability of someone correctly guessing a bank Customer's PN in the first attempt = 1/520
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