a bar=2ibar-3j bar+7k bar,b bar=ibar+2k bar,c bar=j bar-k bar
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Answer:
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Given, ∣
a
∣=1,∣
b
=2,∣
c
=3∣∣
∣
a
∣
b
.
a
=
∣
a
∣
c
.
a
∣
∣
∣
a
+
b
∣
∣
∣
2
=∣
a
∣
2
−
∣
∣
∣
b
∣
∣
∣
2
+∣
c
∣
2
−2
a
.
b
−2
b
.
c
+2
c
.
a
=14
Therefore, ∣
a
−
b
+
c
∣=
14
.
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