Question

A bar 50 mm long is subjected to a tensile stress. If the change in its length is 0.025 mm and young’s modulus is 100 kN/mm^2, the stress in bar is

Answer 1

Answer:

149km long stress in bar

Answer 2

Given:

Length of the bar = 50 mm

Change in length of the bar = 0.025 mm

Young's modulus of the bar = 100 kN/mm²

To find: The stress in the bar.

Solution:

We know that the strain developed in the bar by change in its length will be:

= change in length / original length

= 0.025 / 50

= 0.005

Thus, the stress developed in the bar will be:

= Strain × Young's modulus

= 0.0005 × 100

= 0.05 kN/mm²

Thus, the stress developed in the bar will be 0.05 kN/mm².