A bar accelerates uniformly from 18 Km/h to 36 Km/h m 5 s. Calculate (a) the acceleration and (b) the distance covered by the car in that time.
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acceleration= (36-18) divided by 5
=3.6m/s sq.
by using second equation law of motion.
distance=315km
=3.6m/s sq.
by using second equation law of motion.
distance=315km
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