Question

A bar accelerates uniformly from 18km/h to 36km/h m 5sec.calculate (a)the acceleration and (b)the distance covered by the car in that time

Answer 1

Initial velocity, u=18 km/hr
Final velocity ,V =36 km/hr
Time.t =5 secs
Acceleration ,a=v-u/t
                          =36-18/5
                            =18/5=3.6m/s²
 distance= s
                         =v²-u²=2as
                           36²-18²=2×3.6×s
                           1296-324=7.2s
                            972=7.2s
                             s=972/7.2
                                s=160 mts