a bar is 500 mm long and is stretched to 505mm with a force of 50KN .THE BAR IS 10mm diameter ,calculate the stress and strain
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Given:
A bar is 500 mm long and is stretched to 505mm with a force of 50KN . The bar is if 10mm diameter .
To find:
- Stress
- Strain
Calculation:
- Let's assume the bar to be a cylinder.
- Area of cross-section = πr² = π(10/1000)² = 0.0031 m².
Now, strain will be :
Hope It Helps.
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