Question

A bar magnet having a magnetic moment of 2×10^4JT^-1 is free to rotate in a horizontal plane . A horizontal magnetic field B=6×10^-4T exist in the space.The work done in taking the magnet slowly from a direction parallel to the field to a direction 60 degree from the field is

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Given that:

The initial direction of magnet = parallel to the field =0o

The final direction of the magnet =60o

Magnetic field, B=6×10−4T

Magnetic Moment, M=2×104 JT−1

Work done in rotating a magnet in the magnetic field is given by;

W=B.T(cosθ1−cosθ2)

W=6×10−4×2×104(1−0.5)

W=6J

Thus, It requires a 6 J of work to rotate the magnet from 0o to 60o in the magnetic field.