A bar magnet is at right angles to a uniform magnetic field .The couple acting on the magnet is to be one fourth by rotating it from the position .Tha angle of rotation
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angle of rotation is 14.48 degree
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We know, torque of a couple in a magnetic field B be,
τ= MBsin θ, where M= magnetic moment
τ is directly proportional to sinθ
So τ₁/τ₂ = sinθ₁/sinθ₂
τ/(τ/4)= sin90°/sinθ₂
sinθ₂= 1/4
θ₂= 14.5
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