A bar magnet is oscillating in the Earth’s magnetic field
with a period T. What happens to its period and motion if
its mass is quadrupled?
(a) Motion remains S.H. and period remains nearly
constant
(b) Motion remains S.H. with time period = T/2
(c) Motion remains S.H. with time period = 2T
(d) Motion remains S.H. with time period = 4T
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Answer:
Explanation:option cis correct.
The relation between time period and mass is T1²/T2²=m1/m2
T1²/T2²=m/4m
T1²/T2²=1/4
T1/T2=1/2
T2=2T1
So motion remains same.
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