Physics, asked by dhrumzZ2672, 8 months ago

A bar magnet is oscillating in the Earth’s magnetic field
with a period T. What happens to its period and motion if
its mass is quadrupled?
(a) Motion remains S.H. and period remains nearly
constant
(b) Motion remains S.H. with time period = T/2
(c) Motion remains S.H. with time period = 2T
(d) Motion remains S.H. with time period = 4T

Answers

Answered by karannnn43
1

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Answered by maddulamounika111
0

Answer:

Explanation:option cis correct.

The relation between time period and mass is T1²/T2²=m1/m2

T1²/T2²=m/4m

T1²/T2²=1/4

T1/T2=1/2

T2=2T1

So motion remains same.

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