Physics, asked by neerajk3937, 1 month ago

A bar magnet of magnetic dipole moment 10 Am2 is in stable equilibrium. The work done to rotate the magnet through 60° in a magnetic field of 0.2T is (1) 1 / 1 (2) 2J (3) 1J (4) 4J

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Answered by jeykanth54321

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Answer:

The work done to rotate the magnet through 60° is 1J

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