Question

A bar magnet of magnetic moment 1.5 J/T lies parallel to the direction of a uniform magnetic field of 0.22 T. What is the torque acting on it?​

Answer 1

Answer:

Here m = 1.5J/T, B = 0.22T (a) W = - mB(cosθ2 - cosθ1) (i) θ1 = 0∘ (along the field) θ2 = 90∘ (perpendicular to the field) W = - 0.33(0 - 1)J .