A bar magnet of magnetic moment
100 Am’is bent at its midpoint such that,
the two parts make an angle of 120°. The
new magnetic moment is
(A) 100V2Am
(B) 100 Am
(C) 50/3Am
(D) 50 Am
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Answer:
the net vector would be root{(M/2)^2+(M/2)^2+2×M/2×M/2×cos120°} in the direction 60° east of north.
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