Question

A bar magnet of magnetic moment 200 A-m2 is suspended in a magnetic field of intensity 0.25 N/A-m. The torque required to deflect it through 300 is ___________.

Answer 1

CORRECT QUESTION :–

▪︎ A bar magnet of magnetic moment 200 A-m2 is suspended in a magnetic field of intensity 0.25 N/A-m. The torque required to deflect it through 30⁰ is ___________.

ANSWER :–

▪︎ Required torque is 25 N-m.

EXPLANATION :–

GIVEN :–

• Magnetic moment (M) = 200 A-m²

• Magnetic field (B) = 0.25 N/A-m

• Angle (θ) = 30⁰

TO FIND :–

Torque (τ) = ?

SOLUTION :–

▪︎Torque Definition :–

The force that causes rotation is called Torque .

▪︎ FORMULA :–

➪ τ = (M)(B)sin(θ)

▪︎ Now put the values –

=> τ = (200)(0.25)sin(30⁰)

=> τ = (200)(0.25)(½)

=> τ = (100)(0.25)

=> τ = 25 N-m