Question

A bar magnet of volume 2 x 10-5 m

3 has a uniform magnetization of

6000 A/m. What is its magnetic dipole moment?

3rd question.​

Answer 1

Given info : A bar magnet of volume 2 × 10⁻⁵ m³ has a uniform magnetization of  6000 A/m.

To find : the magnetic dipole moment of the bar magnet is ...

solution : well, intensity of magnetization is the ratio magnetic dipole moment to the volume of the magnet.

⇒ $\text{magnetization}=\frac{\text{magnetic dipole moment}}{\text{volume of bar magnet}}$

here, magnetization = 6000 A/m

volume of the bar magnet = 2 × 10⁻⁵ m³

so, the magnetic dipole moment = magnetization × volume of the bar magnet

= 6000 A/m × 2 × 10⁻⁵ m³

= 0.12 Am²

therefore the magnetic dipole moment of the bar magnet is 0.12 Am².