Question

a bar of 30mm diameter is subjected to an axial force 75 KN . the stress induced in the member is (a) 106MPa (b)125 MPa (c) 145 MPa (d) 180 MPa​

Answer 1

I think this one (b)125 MPa

Answer 2

Answer:

(a)The stress induced in the member is 106MPa

Explanation:

Given that,

The diameter of bar is 30mm.Conerting it into SI units,we get

$d = 30mm = 30 \times 10 {}^{ - 3} m \\ = 0.03m$

Hence the cross section area the bar is found as given below

$A=\frac{π}{4}d^{2}$

Substituting the diameter we get

$A=\frac{π}{4}(0.03)^{2} \\ = 7.07 \times 10 {}^{ - 4} \: m {}^{2}$

Also given that the axial force acting on the bar is

75KN.Therefore,

$F=75000N$

Now the stress induced in the member is given by the relation

$stress = \frac{axial \: force}{area}$

Substituting the given quantities we get

$stress = \frac{75000}{7.07 \times 10 {}^{ - 4} } \\ = 106.08 \times 10 {}^{6} Nm {}^{ - 2} \\ ≈ 106MPa$

Therefore,The stress induced in the member is 106MPa

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