Question

A bar of soap is 12 cm tall, 6 cm wide and 10 cm long.it has a mass of 415 grams .what is the density of the bar of soap?​

Answer 1

Answer:

h=12cm b=6cm. l=10cm

Volume of soap = lbh

= 12*6*10

= 720cm³

Mass = 415g

Density = mass/volume

= 415/720

= 0.576 g/cm³

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Answer 2

Step by Step Explanation:

Given: The dimensions of bar of soap - 12 cm tall, 6 cm wide and 10 cm long and its mass - 415 grams.

To Find: The density of the bar of soap.

• Density is described as the space an object or substance takes up (volume) in relation to the amount of matter in that object or substance (mass).
• The formula for density is:

        ⇒ $Density = \frac{Mass}{Volume}$

• The Volume of the soap is,

       ⇒ $length\times breadth\times height$

       ⇒ $10\times 6\times 12$

       ⇒$720$ $cm^{3}$

• The density of the soap is

        ⇒  $Density=\frac{415 g}{720cm^{3} }$

        ⇒ $0.576 \frac{g}{cm^{3} }$

Hence, the density of the soap is  $0.576 \frac{g}{cm^{3} }$.